Homework Help

[Future Raptor Ace]

Originally Posted by Azhiri

Okay.. uhmmm... I'll type this as best I can. My way of typing exponents is ^#.

6 + 3^2(4)
----------- = y
7-1

I don't even know what this is supposed to be, it just says "solve". Do you solve the problems using the Order of Operations and replace 'y' with your answer/fraction or..

I'd like to know wtf this is and how to solve it and other nice things.

[6+(4 x 3^2]/(7-1) = y i think that is what you are trying to say... if so then what you have to do is as follows
[6+(4 x 9)]/6 = y
[6+ 36]/6 = y
42/6 = y
7 = y
the instructions should say "simplify" not "solve" becuase saying y = [6+(4 x 3^2]/(7-1) is in fact already some said equation being solved in terms of y
hope this helps

Edit:

Originally Posted by Jalen

This thread is dedicated to the discussion on what makes a good blueberry muffin.


Oh yeah, and if you have any homework/school questions feel free to post them here


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Call me retarded, but I don't understand what it means when somebody says something like "it changed by a factor of 4"

and this whole physics lab is pretty much that

For example, one question is "If a moving cart makes a sticky/inelastic collision with a stationary cart of equal mass, by what factor will the cart's velocity change?"

Although my teacher gave the class this formula to "help find the factor, if you can't do it mentally"

MiVi + MtVt = MiVi + MtVt' ('=prime) (i=incident, t=target)

For pretty much all of them I ended up with Vt' = .16

Now I know that 1/6 is .167,

but I don't understand how I translate that to "by what factor"

ahhh collisions in physics love it lol
when they say changed by a factor of 4 they mean your mass or velocity (depending on what specifically they state in the problem) decreased (sometimes it could be increased that you have to read in the given problem) by a number divided by 4. For example, lets say you velocity initial was 20 m/s and they say velocity final decreased by a factor of 4 it would mean 20/4 which = 5m/s. It would be the same if they said a similar statement about your two masses. If this is still not clear give me the problem and ill help you solve it
If you need help with your physics jalen feel free to pm me at anytime
Mike~

Edit:

Originally Posted by Jalen

I don't know.

The initial velocity was .505m/s, and the final was .301m/s

Those are the velocities of the incident cart of 1030.0g making a sticky collision with a target cart of 526.2g

I don't understand how to find the "factor" by which it changed.

Ok you want to know by what factor did the velocity change...
Ok so you have Vo = .505 and V = .301
so .505(x) = .301
x = .301/.505
x = .596
so you velocity changed by a factor of .596 ... check it
.301 / (.596 your factor) is = to your Vo

[user472884]

I still didn't understand so I just put 4 down for everything,

I'll give the exact numbers later so you guys can try and explain it to me, but it was like freaking a factor of 1/3 and crap

[Future Raptor Ace]

I need help solving this problem, it is a fluid pressure problem and it is annoying the hell out of me.... if anyone here knows how to do this please help..... thanks in a million

The problem says a 3ft wide rectangular gate is pinned at is its center C. Determine the torque M that must be applied to its center to open the gate. The specific weight of water is 62.4 lb/ft^3

The dimensions are 12ft 3ft 3ft 2ft and 2ft if you cant read them..... thanks again

[Rev]

Originally Posted by Future Raptor Ace

I need help solving this problem, it is a fluid pressure problem and it is annoying the hell out of me.... if anyone here knows how to do this please help..... thanks in a million

The problem says a 3ft wide rectangular gate is pinned at is its center C. Determine the torque M that must be applied to its center to open the gate. The specific weight of water is 62.4 lb/ft^3

The dimensions are 12ft 3ft 3ft 2ft and 2ft if you cant read them..... thanks again

Don't know if you solved the problem or not. If not then PM me.

Note: I can't read the dimensions because there is no drawing.

[Future Raptor Ace]

Rev or anyone please help me here im not understanding the derivation of a formula
Ok so
Normal strain x = εx = σa/E - υσb/E where υ = Poisson's ratio (- εx/εy) (-lateral strain / axial strain)
Normal strain y = εy = -υσa/E + σb/E where υ = Poisson's ratio (- εx/εy) (-lateral strain / axial strain)
(a = x) and (b = y)
E = the modulus of elasticity

Now from the two equations above how does it come to these two equations below which are normal stress x and y ?

σx = [E/(1-υ^2)](εx + υεy) (eq. 1)
σy = [E/(1-υ^2)](εy + υεx) (eq. 2)
I am solving for P ( a tensile force) so I know I need to solve for the two equations above and relate them to P/A. The only thing that is bothering me is I have no idea where (eq. 1) and (eq. 2) come from or how they are derived..... please help! Thanks!
Is this a Morh's Circle im missing?

[Victor]

lolol seriusly bro that aint too hard. you shoulda just asked me instead of the peeps in here who dont study that stuff. its a shame tho that they arent as smart as us. i try to rub it in sometimes too hahah

[Future Raptor Ace]

Originally Posted by Victor

lolol seriusly bro that aint too hard. you shoulda just asked me instead of the peeps in here who dont study that stuff. its a shame tho that they arent as smart as us. i try to rub it in sometimes too hahah

Your response did not help answer my question

[user472884]

He's just jelly that he doesn't know how to type sigma

[AceTone]

The "I'm more awesome than..." thread is that-a-way.

My sig can be used as a visual.

[Future Raptor Ace]

Originally Posted by Jalen

He's just jelly that he doesn't know how to type sigma

lol
If anyone still knows how to help please do, non of the classmates im friends with understand it either