Homework Help

[user472884]

*places a web of trip wire so once you get up you will set off exactly 17.8 landmines placed in your outline*

Who's the clever one now?

[sumi1]

Originally Posted by Jalen

This thread is dedicated to the discussion on what makes a good blueberry muffin.


Oh yeah, and if you have any homework/school questions feel free to post them here


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Call me retarded, but I don't understand what it means when somebody says something like "it changed by a factor of 4"

and this whole physics lab is pretty much that

For example, one question is "If a moving cart makes a sticky/inelastic collision with a stationary cart of equal mass, by what factor will the cart's velocity change?"

Although my teacher gave the class this formula to "help find the factor, if you can't do it mentally"

MiVi + MtVt = MiVi + MtVt' ('=prime) (i=incident, t=target)

For pretty much all of them I ended up with Vt' = .16

Now I know that 1/6 is .167,

but I don't understand how I translate that to "by what factor"

How you got these numbers? I think it should be 2.

[Azhiri]

-doesn't get up-
-ever-

[user472884]

Originally Posted by sumi1

How you got these numbers? I think it should be 2.

I don't know.

The initial velocity was .505m/s, and the final was .301m/s

Those are the velocities of the incident cart of 1030.0g making a sticky collision with a target cart of 526.2g

I don't understand how to find the "factor" by which it changed.

[sumi1]

Originally Posted by Jalen

I don't know.

The initial velocity was .505m/s, and the final was .301m/s

Those are the velocities of the incident cart of 1030.0g making a sticky collision with a target cart of 526.2g

I don't understand how to find the "factor" by which it changed.

hmm, you said that two carts are of equal masses. since one cart was stationary before the collision, the initial momentum of the system is M V. after the collision, two carts stick together, so mass is now 2M. applying momentum conservation, final velocity of the combined body should be V/2.

[user472884]

Originally Posted by sumi1

hmm, you said that two carts are of equal masses. since one cart was stationary before the collision, the initial momentum of the system is M V. after the collision, two carts stick together, so mass is now 2M. applying momentum conservation, final velocity of the combined body should be V/2.

I'm omitting the trial with the equal masses.... I did it about 20 times and I could not get an error lower than 30%

The trials with unequal masses have much lower errors, so I'm just going to focus on them

[AceTone]

A = πr²
= π(r)²

What happens to the area if you double the radius of a circle:

= π(2r)²

= π(2)²(r)²
= π(4)(r)²
= 4(πr²)
= 4(A)

Doubling the radius increases the area by a factor of 4.

[user472884]

sooooooo.......... (in the gayest voice I can do)

For the one where the incident cart is about twice as heavy

(2Mi)Vi + 0 = (2Mi)Vi' + MtVi' (since the velocities are the same)
(2Mi)Vi = (2Mi)Vi' + MtVi'

my retard sense is tingling quite vigorously now.

And for the next trial where the target cart is about twice the mass

MiVi = MiVi' + (2Mt)Vi'

I DAWN GITTIT

[Fall]

Yes, create a homework help thread after I graduate HS >_<

[AlizéeInspired]

Originally Posted by Fall06

Yes, create a homework help thread after I graduate HS >_<

Yeah, exactly what I was thinking...